Half deck Berzerk/Freaks your deck is Lola Cornelia and Boris Piotr your opp. has Gabrielle Lucia Miss Lulabee Eugene ... Lets say you just played Boris on the first round with 5 pillz and you won, you get 4 damage and poisioned your opp. Second round you sacrifice and save your pillz, your opp. plays and hits you for 8 damage with Fury he/she only has 4 pillz left, on the third round you play Cornelia with Fury, your opp. has 8 life left, after you win with Cornelia how much life does your opp. have left ????
8 life, furied hit drags them to 5. Poison to 3, Eugene to 5, Cornelia to 2.
Or 8 to 5, to 7 and 4 and poison to min of 3.
Answer: Not to a KO, but there's a possibility that your opponent KOs you in turn. Depending on what cards were played at what times when you didn't specify any card and did or did not the other player spend their pillz on round three.
Assuming a 12 life format.
Hit with Boris (8 Life), second turn poison (6 Life), Furious Cornelia 3 damage (3 Life) followed by half of her bonus + her ability (1 Life).
However, two of the opponents cards can screw this up. Gabrielle and Eugene can both negate 2 damage on the first and third rounds and Lucia has to have been the card played on round 2, meaning at least one of them had to have been played.
Therefore, your opponent has somewhere between 3 to 1 Life depending on when those cards were played.
I asked this question not to trick anyone, I was pretty sure I would get a KO on the third round but I didn't, I was confused but after review I see my mistake, first round opp. played Miss Lulabee I win with Boris, second round opp. plays Lucia with Fury and I sacrifice Lola, third round I played Cornelia with Fury opp. played Eugene ... Now it it is easy to answer my question ....
Yes, defeat: +x life happens before -x opp.life, that's why Eugene's ability kicked in first, before Cornelia's. And poison happens last.