Resolving a round Marsell4000 - Veteran - Saturday 19/08/2006, 18:58
Can someone please help explain to me how when I have 3 power and use 4-5 pills I lose to a character that has 2 power and uses no pills? Makes no sense to me and is a little frustrating. There were no abilities or bonuses to take into account.
Simply, attack power doesn't guarantee wins. There's always a chance, although a small one, for the underdog to come back. Depending on how great the spread of attack is, depends on the chance. For example a 49 Attack vs a 1 Attack the 1 attack has a very tiny chance.
In your case, a 3 power with 5 pillz or 15 Attack, vs a 2 Power with 1 pillz which is 2 attack, because the spread is only 13 attack, it has a much larger chance than the first example (though it's still fairly low), to come back and win.
And it seems that after about 5 or 6 pills, how high your attack or pill count is does not further reduce your chance of losing to freakish luck.
Also, it seems to me you can always count on certain cards to let you down. My Lao has most certainly lost over 80% of fights when his total and pills are both higher than his opponent. Lao is capable of only 1 knocking 1 square of an opponent's health in 2 attacks. Vladmir and 1 or 2 others were also seriously unreliable at low levels.
I have also lost all 4 rounds of a game when my pill count and attack total for every round is higher than my opponent.
But it comes around. I've had a 6 win streak where I probably only won the first 3 or 4 by being lucky.
Ok, so it is freakish luck. I had guessed it must work on the odds system you mention storm, thanks.
Zubbus - Yes I have had the same with wins, but its more frustrating losing than it is satisfying winning in that way for me. I'd much prefer to know I'd beaten my opponent on skill rather than luck.
I was thinking that it would be better to have the total attack points count as the winner with no luck factored in, but i suppose the system is like that to give those with a really bad hand of cards a chance.
Oh well, play on. Thanks for answering my question.
"In your case, a 3 power with 5 pillz or 15 Attack, vs a 2 Power with 1 pillz which is 2 attack, because the spread is only 13 attack, it has a much larger chance than the first example (though it's still fairly low), to come back and win"
yes its true 3 (power) times 5 (pillz) equals 15 (attack), but that would mean that adding no pillz at all will give you no attack at all (3 times 0 equals 0)
A 3 power with 5 pillz gives 18 attack (3 attack from the card plus 3 times 5)
so the opponent had in fact an 18 procent chanche of winning (4 divided by 22)
3 power with 5 pillz equals 18 attack (chanche of win, 81.81%)
2 power with 1 pillz equals 4 attack (chanche of win, 18.18%)
spread of attack is 22.
following the wrong calculations from stormwind the opponent would only had a chanche of 11.76%
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