Are the winners of the dailys generally type 1 or type 2?
I only play type 1 because of the skill involved. The problem is I can only get to 18 matches on a daily tourney in type 1 and the best I can generally do is be 15 and 3 with around 260-270 points. This means I am not playing enough matches to get to that 400 point mark. I couldn't even win all the matches with average 20 points each to get to the top 5 spots. The best I have done in a daily is around 40th place.
I am averaging about 3 minutes and 20 seconds a match in a tourney I place well in and about 3 minutes and 45 seconds to 4 minutes a match in a tourney I do somewhat poorly in. This meens that players that play in type 2 with all or nearly all 5 star cards could potentially end a match in 38% faster (40-25/40). That meens that compared to my lowest average time in type 1 someone with equal type 2 skill could complete almost 29 matches. Now if you win 83% like I do in my best games in type 1 and average around 14 points you can get roughly 338 points.
Now there is something wrong here. The higher skilled daily game(type 1) has a lower chance to place higher than a less skilled game(type 2). I can get 260 points in daily type 1 while an equal skilled player as me in type 2 can get 338 points. Here is the math (338-260/33 = 28%. Type 2 can perform 28% better than type 1 in equal conditions.
There are errors in my math, though it is close.
What is the solution? You tell me?
Winners are mostly T2 players though i've won once in T1.
your problem is that you are spending way too long on your battles. in DT you have to win the battle in 2 rounds (maybe 3 if you face Shakra or the like in the first our 2nd round). your battles should then not take more than half the time you listed.
If you're using all 5 star cards in a T2 DT, you won't win. Everyone who does well in the T2 Dalies use 26* decks to maximize points. When low star cards beat high star cards, you get more points. This is how people constantly break teh 400 point mark and win all those daily tournies
Korrupt, that is what I meen by my math being off. In type 1 the average 4 cards delt will be 12-13 stars with a certain probability of being able to win in two rounds, and in type 2 the avg. 4 cards delt will have a greater probability of being able to end the match in two rounds.
Here is a possible solution since mathamatically T2 has an advantage in the DT, and it would be lame to have seperate T2 and T1 DT since the clintz would be half as much.
There could be a handicap. T2 high score in the DT minuts T1 high score in the DT. This will give you the handicap. Say T2 high is 400 and T1 high is 300, that makes the handi cap 100. 100 points are added to the T1 high fo a total of 400 points Now this would create a tie for first. The tie can be broken by a certain factor, and that factor is average points per match. Basically who ever is more effecient breaks the tie. Now this formula would have to be dont to places 1 - 75 in T1 and T2 for a total of 150 places.
I am sure people can think of better ways to break the tie for for the most part it would eliminate the advante T2 has over T1 in the DT. What do you think?
T2 Tourny has just as much strategy in play and deck building as T1. You have to factor for more Nuke cards played against you that you'll have to defend against, have enough damage to actually win, and at the same time, keep the star count down so you can get all the points you need. In game, you've got to use pillz very wisely because one mistake, whether you miscalculated, or overestimated in pill use, or attack, you're done for.
That being said, maybe some sort of handicap system could be devised, but putting it into actual use could be trouble. I know nothing about coding games, but it sounds like it would take quite a bit to write it into the code that runs the game.....
Yes it seems possible as long as you dont get any type 2 players with equal or better skill as you. Clearly the daily is not balanced, and for the sake of fairness the two types of decks should not be bundled into one tourney where they compete against each other by over all score at the end. A mathamatical system should be developed that CAN be integrated to eleminate the amount of error in scoring that is A) is given to the T2 or B) taken away from T1.
Mathamatical models shouldnt be that hard to integrate. This is a great game with great developers, and as this game matures bugs, error, and other mistakes are found. This error in scoring of T1 vs. T2 in the daily tourney is an example of an error in the game that is exploitable to give an advantage to any T2 player in overall scoring, and is even more exploitable for the top tier players of T2 where an exponential amount of clintz is awarded for the top scores.
There is not much to disagree with here, I am just pointing out that there is a MATHAMATICAL advantage that T2 has over T1 in the DT. I am not disputing the possibility of a T1 winning. The probability is low but it is possible. What I am looking for and the community should be looking for as well is to iron out exploits so the game is fair.
I could start playing T2 until the exploit is fixed but that defeats my purpose.
Forgot to put this in my last post. I think it would be interesting to see in the top 150 spot in each daily tourney how many are T1 and how many are T2. It would be interesing to see a distribution , such as how many T1 anf T2 are in place 150-141, 140-131, 130-121, 120-111, 110-101, and so fourth until place 1.
Here is a possible quick fix, of course there wilbe some issues but it may fit right into the program fairly easily. Avergage the top 150 T2 scores and average the top 150 T1 scores. Take the percentage difference and give all the T1 that x(1+%) or minus the x(%) from the T2.
Here the example.
T2 average is 300 and T1 is 250. (300-250)/300 = 16.67%.
Scenerio 1) Now player JabaDoo is a T1 player and scored 270 points. His new score is 270(1+.1667). That is now 270 + 45, for a total of 315 points.
Scenerio 2) JabaDoo is a T2 player now and scored 350 points. His new score is 350 - 350(.1667). That is 350 - 58, for a total of 292 points.
I am sure there is a better mathamatical model, but that is what programers for.